How to get odd numbers from array in JavaScript using filter() method?

 To get the odd numbers from an array in JavaScript using the filter() method, you can use the following code:

const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

const oddNumbers = numbers.filter(number => number % 2 !== 0);

console.log(oddNumbers); // Output: [1, 3, 5, 7, 9]

In this example, the filter() method is used to create a new array called oddNumbers, which includes only the elements of the original numbers array that are odd.

The callback function in the filter() method checks if each element of the numbers array is odd or not. It returns true for each odd number, and false for even numbers. The filter() method then returns a new array with all the elements that returned true in the callback function.

The resulting oddNumbers array contains all the odd numbers from the original numbers array, and the output of the console.log() statement is [1, 3, 5, 7, 9].